<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Operators on Chen Kai Blog</title><link>https://www.chenk.top/en/tags/operators/</link><description>Recent content in Operators on Chen Kai Blog</description><generator>Hugo</generator><language>en</language><lastBuildDate>Fri, 15 Oct 2021 09:00:00 +0000</lastBuildDate><atom:link href="https://www.chenk.top/en/tags/operators/index.xml" rel="self" type="application/rss+xml"/><item><title>Functional Analysis (8): Spectral Theory — Decomposing Operators</title><link>https://www.chenk.top/en/functional-analysis/08-spectral-theory/</link><pubDate>Fri, 15 Oct 2021 09:00:00 +0000</pubDate><guid>https://www.chenk.top/en/functional-analysis/08-spectral-theory/</guid><description>&lt;p>When I first saw the word &amp;ldquo;spectrum&amp;rdquo; used for an operator I assumed it was a fancy synonym for &amp;ldquo;set of eigenvalues.&amp;rdquo; That is the right intuition for matrices and for compact operators, and it is exactly what one wants in introductory linear algebra. The trouble is that it is wrong as soon as the operator is not compact. The position operator &lt;span class="math-inline">$(Mf)(x) = x f(x)$&lt;/span>
 on &lt;span class="math-inline">$L^2[0, 1]$&lt;/span>
 has no eigenvalues: any eigenfunction would have to satisfy &lt;span class="math-inline">$x f(x) = \lambda f(x)$&lt;/span>
 a.e., which forces &lt;span class="math-inline">$f = 0$&lt;/span>
 everywhere away from a single point, hence &lt;span class="math-inline">$f = 0$&lt;/span>
 in &lt;span class="math-inline">$L^2$&lt;/span>
. And yet the operator is clearly not invertible, since &lt;span class="math-inline">$\lambda I - M$&lt;/span>
 is multiplication by &lt;span class="math-inline">$x - \lambda$&lt;/span>
, which fails to be boundedly invertible whenever &lt;span class="math-inline">$\lambda \in [0, 1]$&lt;/span>
.&lt;/p></description></item><item><title>Functional Analysis (6): Bounded Linear Operators and the Big Theorems</title><link>https://www.chenk.top/en/functional-analysis/06-bounded-operators/</link><pubDate>Mon, 11 Oct 2021 09:00:00 +0000</pubDate><guid>https://www.chenk.top/en/functional-analysis/06-bounded-operators/</guid><description>&lt;h2 id="why-this-article-is-where-the-theory-catches-fire" class="heading-anchor">Why This Article Is Where the Theory Catches Fire&lt;a href="#why-this-article-is-where-the-theory-catches-fire" class="heading-link" aria-label="Permalink to this section" title="Copy link to this section">#&lt;/a>
&lt;/h2>&lt;p>For five articles I have been building scaffolding: metric and normed spaces, Hilbert spaces, dual spaces, weak topologies. None of those individually felt very impressive — I am, after all, just doing topology and linear algebra in slightly more general settings than usual. The point at which functional analysis genuinely &lt;em>delivers&lt;/em> is right here, in the three great theorems of Banach space operator theory: the &lt;strong>Uniform Boundedness Principle&lt;/strong>, the &lt;strong>Open Mapping Theorem&lt;/strong>, and the &lt;strong>Closed Graph Theorem&lt;/strong>. Each of these takes a piece of &amp;ldquo;pointwise&amp;rdquo; or &amp;ldquo;set-theoretic&amp;rdquo; data — pointwise boundedness, surjectivity, closedness of the graph — and concludes a global structural property — uniform boundedness, openness, continuity — that has no analog in finite dimensions because finite-dimensional linear algebra makes them all true automatically.&lt;/p></description></item></channel></rss>